Minneapolis Mayoral Election 2017
Re: Minneapolis Mayoral Election 2017
With the current system of three choices and 15 candidates, there are 2730 possible ballots. With six choices there are 3,603,600. Hand counting with six will be a time suck, but very easy for a computer to do.
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- IDS Center
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Re: RE: Re: Minneapolis Mayoral Election 2017
The number of possible combinations of ballots has exactly zero to do with the algorithmic complexity of counting.With the current system of three choices and 15 candidates, there are 2730 possible ballots. With six choices there are 3,603,600. Hand counting with six will be a time suck, but very easy for a computer to do.
The growth in the number of possible ballot combinations is factorial in the number of candidates, even more rapid growth than exponential. The counting is still polynomial.
"Exponential," even used colloquially, gives an impression of a much harder job than it actually is. I get that "polynomial" can turn people off. So I just tell people, "it's not bad at all," and if they want more detail I explain that computer people are professionally trained in this stuff and if you don't trust me (which is fine!) then just go ask another computing professional, preferably someone with a degree.
Re: Minneapolis Mayoral Election 2017
I don't get the Hoch in this grouping. Well, I do, but personally I think it says something about how little people actually understand issues in city elections. They've heard of Hoch ($$$) and he seems like a good guy, so okay.I even know someone who did Frey/Hodges/Hoch!
I think it's entirely possible. Heck, at the caucuses I was Frey/Hodges. Something Frey definitely didn't seem to see as making much sense when I spoke to him beforehand.I think this actually bodes worse for Betsy, because I think Jacob might be sitting on a larger share of her 2nds than people think.
That said, someone who voted NLP first is probably an equity voter and thus probably not particularly likely to rank Frey second. Only slightly less true for Dehn.
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- Capella Tower
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Re: Minneapolis Mayoral Election 2017
Well, regardless, it's Frey: http://vote.minneapolismn.gov/results/2 ... tabulation
Re: Minneapolis Mayoral Election 2017
Yeah, the exact number of combinations doesn't really matter. You could pretty much keep the ranking of voters in some sort of table or entry from first to sixth (or whatever) and once the first choice drops out, push their other ranks "ahead" so the "first choice" vote is actually a "current choice" vote. If someone's second/third/whatever choice drops out, keep pushing until you hit a candidate that's still in or you've exhausted the rankings. Rinse and repeat until you get someone who's crossed the threshold or has the most after there's just two candidates left.
It's also not terribly difficult to do by hand (versus only having three, anyways.)
It's also not terribly difficult to do by hand (versus only having three, anyways.)
Re: Minneapolis Mayoral Election 2017
No surprise, then, and it was the Hodges second and thirds that put him over the top.
Hoch spent all that money and wound up fourth. And no one actually getting to 50%-1 and 11914 effectively disenfranchised because we only get to rank 3 (or they chose to rank fewer than 3). ETA: Oops, that exhausted number was just in the last round. Total was 22,835.
ETA: Oh, and Frey getting 9888 votes when Hoch was eliminated, about 2/3 of those reallocated.
Hoch spent all that money and wound up fourth. And no one actually getting to 50%-1 and 11914 effectively disenfranchised because we only get to rank 3 (or they chose to rank fewer than 3). ETA: Oops, that exhausted number was just in the last round. Total was 22,835.
ETA: Oh, and Frey getting 9888 votes when Hoch was eliminated, about 2/3 of those reallocated.
Last edited by amiller92 on November 8th, 2017, 2:07 pm, edited 1 time in total.
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- Foshay Tower
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Re: Minneapolis Mayoral Election 2017
So it was
1. Frey
2. Dehn
3. Hodges
4. Hoch
5. Levy-Pounds
As for Levy-Pounds support, 40% went to Dehn, 30% to Hodges, 20% to Frey, and 10% to Hoch.
Hoch supporters remaining went 60% to Frey, 20% each to Hodges and Dehn.
Hodges supporters remaining were 50% Dehn, 50% Frey.
1. Frey
2. Dehn
3. Hodges
4. Hoch
5. Levy-Pounds
As for Levy-Pounds support, 40% went to Dehn, 30% to Hodges, 20% to Frey, and 10% to Hoch.
Hoch supporters remaining went 60% to Frey, 20% each to Hodges and Dehn.
Hodges supporters remaining were 50% Dehn, 50% Frey.
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- Capella Tower
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Re: Minneapolis Mayoral Election 2017
Yeah, Betsy's 2nd/3rds went more to Dehn than Frey (barely), Frey's biggest bump (aside from his lead thanks to 1st choice votes) was from Hoch.
Which.
Which.
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- Foshay Tower
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Re: Minneapolis Mayoral Election 2017
Most of this was people not putting a 2nd or 3rd. Meaning that adding more on the back end would not enfranchise many people.And no one actually getting to 50%-1 and 11914 effectively disenfranchised because we only get to rank 3 (or they chose to rank fewer than 3). ETA: Oops, that exhausted number was just in the last round. Total was 22,835.
Re: RE: Re: Minneapolis Mayoral Election 2017
Heh, I'm one of those professionally-trained computer people, whoops! I should have known my audience and preferred the more precise term "factorial" to "exponential," but it was this factorial growth I was alluding to. I agree that the algorithmic complexity of counting is polynomial, but the number of permutations still matters.The number of possible combinations of ballots has exactly zero to do with the algorithmic complexity of counting.With the current system of three choices and 15 candidates, there are 2730 possible ballots. With six choices there are 3,603,600. Hand counting with six will be a time suck, but very easy for a computer to do.
The growth in the number of possible ballot combinations is factorial in the number of candidates, even more rapid growth than exponential. The counting is still polynomial.
"Exponential," even used colloquially, gives an impression of a much harder job than it actually is. I get that "polynomial" can turn people off. So I just tell people, "it's not bad at all," and if they want more detail I explain that computer people are professionally trained in this stuff and if you don't trust me (which is fine!) then just go ask another computing professional, preferably someone with a degree.
My understanding from this page is that the current counting process actually separates the ballots into literal piles and enters their counts, separately, into a spreadsheet. If that's the case, the jump from 3 to 6 would indeed overwhelm the existing process. It is of course possible to devise other ways of counting, though if a hand-count or hand-audit is a requirement, it becomes more challenging.
Re: Minneapolis Mayoral Election 2017
Strib is calling it for Frey
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Re: Minneapolis Mayoral Election 2017
Kinda cool that you can (sorta) see how many voters went "bullet ballot" (i.e. chose only their favorite candidate, did not rank others) by moving through the elimination rounds.
2,630 voters did not rank any of the top 5 candidates, only ranking among the 14 joke candidates.
2,119 voters did not rank any of the top 4, only ranking Levy-Pounds (*and possibly previously eliminated candidates)
6,172 voters did not rank any of the top 3, only ranking Hoch (*and possibly previously eliminated candidates)
Adam, there's no guarantee that many voters were "effectively disenfranchised", because we don't know IF they actually ranked more than one candidate. I'm not saying we shouldn't be able to rank 6 candidates like St. Paul, we definitely should! (EDIT: I see LakeCharles already pointed this out)
2,630 voters did not rank any of the top 5 candidates, only ranking among the 14 joke candidates.
2,119 voters did not rank any of the top 4, only ranking Levy-Pounds (*and possibly previously eliminated candidates)
6,172 voters did not rank any of the top 3, only ranking Hoch (*and possibly previously eliminated candidates)
Adam, there's no guarantee that many voters were "effectively disenfranchised", because we don't know IF they actually ranked more than one candidate. I'm not saying we shouldn't be able to rank 6 candidates like St. Paul, we definitely should! (EDIT: I see LakeCharles already pointed this out)
Re: Minneapolis Mayoral Election 2017
Do we know that? I don't think so. There were 2630 exhausted in the first round of elimination. Presumably most of those had no second or third, but some of them could have included 3 minor candidates. I don't think we can guess about any of the later rounds.Most of this was people not putting a 2nd or 3rd. Meaning that adding more on the back end would not enfranchise many people.
Re: Minneapolis Mayoral Election 2017
First, that's only roughly half of the exhausted ballots. Seconds, that's why I said "(or they chose to rank fewer than 3)"Kinda cool that you can (sorta) see how many voters went "bullet ballot" (i.e. chose only their favorite candidate, did not rank others) by moving through the elimination rounds.
2,630 voters did not rank any of the top 5 candidates, only ranking among the 14 joke candidates.
2,119 voters did not rank any of the top 4, only ranking Levy-Pounds (*and possibly previously eliminated candidates)
6,172 voters did not rank any of the top 3, only ranking Hoch (*and possibly previously eliminated candidates)
Adam, there's no guarantee that many voters were "effectively disenfranchised", because we don't know IF they actually ranked more than one candidate. I'm not saying we shouldn't be able to rank 6 candidates like St. Paul, we definitely should! (EDIT: I see LakeCharles already pointed this out)
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- IDS Center
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Re: Minneapolis Mayoral Election 2017
Yes, that's essentially the algorithm I and a colleague worked out in about 20 minutes on Facebook (complete with pseudocode!). There may be even faster algorithms. It turns out that for this algorithm, the majority of the time is spent preparing the data (sorting, etc.) for the fastest possible processing. A better ballot design might even eliminate the need for that.Yeah, the exact number of combinations doesn't really matter. You could pretty much keep the ranking of voters in some sort of table or entry from first to sixth (or whatever) and once the first choice drops out, push their other ranks "ahead" so the "first choice" vote is actually a "current choice" vote. If someone's second/third/whatever choice drops out, keep pushing until you hit a candidate that's still in or you've exhausted the rankings. Rinse and repeat until you get someone who's crossed the threshold or has the most after there's just two candidates left.
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- Foshay Tower
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Re: Minneapolis Mayoral Election 2017
Do we know that? I don't think so. There were 2630 exhausted in the first round of elimination. Presumably most of those had no second or third, but some of them could have included 3 minor candidates. I don't think we can guess about any of the later rounds.Most of this was people not putting a 2nd or 3rd. Meaning that adding more on the back end would not enfranchise many people.
We know that there were 104,297 first place votes in total, there were 92,273 second place votes in total, and 78,188 third place votes in total.
So 12,024 people elected not to put a second choice, and 26,109 elected not to put a third choice. This represents the majority of the exhausted ballots.
Unless all of those people voted for Dehn or Frey first.
Last edited by LakeCharles on November 8th, 2017, 2:37 pm, edited 1 time in total.
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Re: RE: Re: Minneapolis Mayoral Election 2017
Yeah, that seems on the surface like a bad algorithm, but I haven't put any thought into the best way to process ballots by hand.My understanding from this page is that the current counting process actually separates the ballots into literal piles and enters their counts, separately, into a spreadsheet. If that's the case, the jump from 3 to 6 would indeed overwhelm the existing process. It is of course possible to devise other ways of counting, though if a hand-count or hand-audit is a requirement, it becomes more challenging.
What's frustrating about this is a computer scans the ballots initially. Literally all that's needed is for the computer to remember each ballot and a pointer to it's "current" ranked candidate. Then it's simply a matter of counting and updating pointers as candidates are eliminated. Easy to do in a computer, probably much harder by hand.
The bottom line for me is that there's been a collossal dropping of the ball by someone(s) somewhere to not have certified counting software after EIGHT FRICKING YEARS!
Re: Minneapolis Mayoral Election 2017
Right, I was confused briefly as to how there could have been more "missing" third place ballots than exhausted ballots, but the answer is some number of bullet voters for Frey and Dehn.
Unless all of those people voted for Dehn or Frey first.
Okay, I agree that it doesn't look like getting to rank more would make much difference in the exhausted ballots.
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- IDS Center
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Re: Minneapolis Mayoral Election 2017
None of my ranked candidates won and while my fourth choice would have been Frey, I'm still pretty uneasy that I didn't get to have a voice in that.
Re: Minneapolis Mayoral Election 2017
Didn't you rank Dehn first? How was your voice not counted (I ranked him third, so mine was).
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